Posted by **kiki** on Thursday, April 25, 2013 at 3:16pm.

a potato chip manufacturer has been accused of shortchanging their customers with 10 ouce of bags potato chips. a sample of 50 of that company's 10 ounce bags was take, and it was found that the average weight was 9.8 ounces with a standard deviation of 0.3 ounces.can we conclude that the company's bags of potato chips are less than 10 ounces?use 5%significance level

- math -
**PsyDAG**, Friday, April 26, 2013 at 3:21pm
Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

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