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July 22, 2014

July 22, 2014

Posted by **:D** on Thursday, April 25, 2013 at 3:12pm.

6,-14, and 4+3i

- Math Algebra -
**Steve**, Thursday, April 25, 2013 at 3:18pm4-3i must also be a root, so we have

p(x) = (p-6)(p+14)(p-(4+3i))(p-(4-3i))

= (p-6)(p+14)((p-4)^2 + 3^2)

= (p-6)(p+14)(p^2-8p+25)

= p^4 - 123p^3 + 872p - 2100

- Math Algebra -
**:D**, Thursday, April 25, 2013 at 3:20pmPerfect Thanks,

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