Posted by Chade on .
A 13.8 g piece of Zn metal was heated to 98.6 oC and then dropped in 45.6 g of water at 25.0 oC. Assuming that no heat is lost to the surroundings, determine the specific heat capacity of Zn if the final temperature of the water was 27.1 oC C=6461.39
heat lost by Zn + heat gained by water = 0
[mass Zn x specific heat Zn x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute and solve for the one unknown.