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March 29, 2015

March 29, 2015

Posted by **gladys** on Thursday, April 25, 2013 at 12:03pm.

need the ans. asap

- physics - stopping distance -
**Elena**, Thursday, April 25, 2013 at 1:10pmThe reaction time is t =x/v=7.5/10 = 15/20 =22.5/30 = 0.75 s.

The reaction distance for v=25 m/s is x=vt=25•0.75 = 18.75 m.

The acceleration is

a=v²/2s=10²/2•5=20²/2•20=30²/2•45=10 m/s²

The breaking distance for v=25 m/s is

s= v²/2a=25²/2•10=31.25 m

The stopping distance is x+s = 18.75+31.25=50 m

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