Posted by **gibbs** on Thursday, April 25, 2013 at 6:57am.

The function f(x)= ax^3 - bx +c passes through the origin, f(-1)=4/3 and it has an extreme point at x=1

(i) Find the values of a, b and c.

(ii) Sketch the graph

(iii) Find the area bounded by the graph of f(x) and the x-axis between the lines x=-1 and x=1

## Answer This Question

## Related Questions

- MATH TRIGONOMETRY - refer to the polynomial function f(x)= -x(x-1)(x+2) in ...
- extreme value of absolute..... - find the extreme values of the function on the ...
- Math - Given the following LP model (represented abstractly with decision ...
- Calculus - 1. Given the function f defined by f(x) = x^3-x^2-4X+4 a. Find the ...
- pre-calculas - An object is situated so that its center of mass is located at ...
- Calculus - Sketch a graph of the parabola y=x^2+3. On the same graph, plot the ...
- maths - 1. Prove using mathematical induction that 1+2+3+...+n=[ n(n+1)]/2 2. ...
- maths - 1. Prove using mathematical induction that 1+2+3+...+n=[ n(n+1)]/2 2. ...
- math - Consider the cubic graph y = 3x^2 − x^3. (a) Write 3x^2 − x^3...
- calc - The function f is defined by f(x) = x^3 - x^2 - 4x + 4 The point (a,b) is...

More Related Questions