posted by Audre on .
To treat a burn on your hand, you decide to place an ice cube on the burned skin. The mass of the ice cube is 16.0 g, and its initial temperature is -10.4 °C. The water resulting from the melted ice reaches the temperature of your skin, 28.3 °C. How much heat is absorbed by the ice cube and resulting water? Assume that all the water remains in your hand.
q1 = heat absorbed by ice from -10.4 to zero.
q1 = mass ice x specific heat solid ice x (Tfinal-Tinitial).
Note: Tfinal = 0 and Tinitial = -10.4
q2 = heat absorbed to melt ice at zero to liquid at zero.
q2 = mass ice x heat fusion ice
q3 = heat absorbed in water at zero moving to skin temperature.
q3 = mass H2O x specific heat H2O x (Tfinal-Tinitial).
Total heat absorbed = q1 + q2 + q3.