Posted by **ryan** on Thursday, April 25, 2013 at 12:08am.

the school bought a new copy machine which makes 20 copies per minute.the old machine makes 12 copies per minute.francine needs 1000 copies,so she uses both machines.how long will it take to have the copies

- algebra1 -
**ryan**, Thursday, April 25, 2013 at 1:18am
solve the following system of equations by first rearranging them so that they are not in fractional form:

3/(x+2) -2/(x+3)=7y/(3x^2+15x+18)

4(y+3) +1/(y+1)= 11x/(Y^2+4y+3)

- algebra1 -
**Liv4life**, Thursday, April 25, 2013 at 1:20am
Easy x=2 and x=3

- algebra1 -
**ryan**, Thursday, April 25, 2013 at 1:39am
solve the following system of equations by first rearranging them so that they are not in fractional form:

3/(x+2) -2/(x+3)=7y/(3x^2+15x+18)

4(y+3) +1/(y+1)= 11x/(Y^2+4y+3) oh please help oh please my math teach will funk me if i don't get these problem porrect.

- algebra1 -
**Reiny**, Thursday, April 25, 2013 at 8:40am
rate of 1st machine = 20 copies/min

rate of 2nd machine = 12 copies/min

combined rate = 32 copies/min

so to make 1000 copies takes

1000/32 or 31.25 minutes or

31 minutes and 15 seconds

- Note to Ryan - algebra1 -
**Reiny**, Thursday, April 25, 2013 at 8:49am
Please do not post a new question as an answer to an existing problem, it could easily be considered to be an answer and could thus be ignored.

3/(x+2) -2/(x+3)=7y/(3x^2+15x+18)

3/(x+2) - 2/(x+3) = 7y/(3(x+2)(x+3))

multiplyeach term by 3(x+2)(x+3) , the LCD

9(x+3) - 6(x+2) = 7y

9x + 27 - 6x - 12 = 7y

3x - 7y = -15 -----> #1

Repeat the same thing for the 2nd equation, it works out just as simple

Note that y^2 + 4y + 3 = (y+1)(y+3)

Now you have 2 simple linear equations with x and y, and judging by the complexity of the two starting equations, you obviously know how to do that.

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