In the right triangle shown below, the length of AB is 8 units, ¡ÏA measures 60¡ã, sin 60¡ã ¡Ö 0.866,

cos 60¡ã ¡Ö 0.5, and tan 60¡ã ¡Ö 1.73. Approximately how many units long is BC , to the nearest
hundredth of a unit?
A. 4.00

To find the length of BC in the right triangle, we can use the trigonometric ratio of sine.

In this case, we have the following information:
- The length of AB is 8 units.
- The angle A measures 60 degrees.

Using the sine ratio, we have:
sin A = BC/AB

Since we know that sin A is approximately 0.866, we can substitute the values into the equation:
0.866 = BC/8

To find the length of BC, we can multiply both sides of the equation by 8:
0.866 * 8 = BC
BC ≈ 6.928

Therefore, the length of BC is approximately 6.93 units to the nearest hundredth.