Posted by Yvonne on Wednesday, April 24, 2013 at 11:49pm.
Algebra - Reiny, Thursday, April 25, 2013 at 8:23am
factor each part
here is the hardest part
x^3 + 2x^2 - 4x - 8 , using grouping
= x^2(x+2) - 4(x+2)
= (x^2 - 4)(x+2)
= (x+2)(x-2)(x+2) or (x-2)(x+2)^2
= (x-2)(x+2)^2 /((x-2)(x+2)(x^2 + 4)) * (x+1)(3x+5)/((3x+5)(x+2))
= (x+1)/(x^2 + 4) , x ≠ ±2, -5/3
check by picking any value of x other than the restricted values
e.g. let x = 1
= (-9)/(-15)*(16/24) = 2/5
value of (x+1)/(x^2+4) = 2/5
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