Wednesday
March 22, 2017

Post a New Question

Posted by on Wednesday, April 24, 2013 at 10:43pm.

What is the pH of a solution of 40.0 ml of 0.800 M HCl titrated with 4.00 ml of 1.00 M Hydroxyl amine?

  • Chemistry - , Thursday, April 25, 2013 at 3:39pm

    mols HCl = M x L = 0.800 x 0.040 = 0.032
    mols HONH2 = M x L = 1.00 x 0.004 = 0.004
    So you have 0.032-0.004 = 0.028 mols HCl remaining and the volume is 40 + 4 = 44 mL or 0.044 L.
    So M HCl = mols/L and convert that to pH.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question