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April 18, 2014

April 18, 2014

Posted by **trish** on Wednesday, April 24, 2013 at 10:36pm.

F(x)= ln(8-x)

I am totally lost, somebody please help????

- pre calculus -
**Steve**, Thursday, April 25, 2013 at 4:59amy=ln(8-x)

e^y = 8-x

x = 8-e^y

so, f^-1 = 8 - e^x

ln(u) is defined only for u>0, so that means the domain of F is all reals such that 8-x > 0, or x<8.

ln(8-x) has a vertical asymptote where 8-x=0, or x=8.

range is all reals.

domain and range are swapped for the inverse.

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