What is the amount of work produced when 1.0 g of H2O (l) is boiled at atmospheric pressure? Assume the liquid has no volume.
PV = nRT
Calculate V.
Then w = -pdV
This will have the units of L*atm.
To calculate the amount of work produced when 1.0 g of liquid water (H2O) is boiled at atmospheric pressure, we need to understand the concept of work and the changes that occur during boiling.
Work is defined as the energy transfer that results from a force acting on an object and causing it to move. In thermodynamics, work is often associated with changes in volume or pressure.
When water boils, it undergoes a phase change from liquid to gas (vapor). During this process, the volume of water drastically increases due to the formation of gas molecules. However, in this scenario, it is assumed that the liquid water has no volume, which means the boiling process will not cause any change in volume. Consequently, no work is done.
In simple terms, if the liquid water has no volume as stated, it means it cannot expand or exert any pressure to do work. Therefore, the amount of work produced when 1.0 g of water is boiled at atmospheric pressure is zero.