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calculating the molarity of acetic acid in a vinegar sample given that 5.00 of vinegar required 43.50 mL of 0.1050 M NaOH to just reach the methyl red endpoint.

  • chemistry -

    Is that 5.00 mL )0.00500L)vinegar?
    mols NaOH = M x L = ?
    Then M = mols/L soln

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