Posted by ayan on .
What is the real part of (2+i)(6−i)?

Number Theory 
David Kroell,
(2+i)(6−i)=12+6i−2i−i2=12+4i+1=13+4i.
Hence the complex part is 4 and the real part is 13.
Posted by ayan on .
What is the real part of (2+i)(6−i)?
(2+i)(6−i)=12+6i−2i−i2=12+4i+1=13+4i.
Hence the complex part is 4 and the real part is 13.