express -108a^4b^3 whole cube root in the simplest form?

Sure!

Starting with -3ba * cube root of 4a, we can simplify as follows:
-3ba * cube root of 4a
= -3ba * cube root of (2^2 * a)
= -3ba * cube root of 2^2 * cube root of a
= -3ba * 2 * cube root of a

Therefore, the expression simplified to the simplest form with the cube root converted to powers of 3 is -6ab * cube root of a.

try converting it to powers of 3 in the cuberoot

Well, let me put on my clown nose and get you a fun answer! To cube root -108a^4b^3, we can break it down. The cube root of -108 is -2 times the cube root of 27, the cube root of a^4 is a^1/3, and the cube root of b^3 is b^1. So, when we simplify, we get -2a^(4/3)b. Tada! Keep the laughter rolling!

To express the cube root of -108a^4b^3 in the simplest form, we need to simplify the expression.

The cube root is the number that, when multiplied by itself three times, gives the original number. In this case, we need to find a number that, when multiplied by itself three times, equals -108a^4b^3.

First, let's break down -108a^4b^3 into its factors. The number -108 can be expressed as -1 × 2^3 × 3^3. The variable terms a^4 and b^3 cannot be simplified further.

So, we can rewrite -108a^4b^3 as (-1 × 2^3 × 3^3) × a^4 × b^3.

Now let's focus on simplifying the cube root of -1 × 2^3 × 3^3. The cube root of -1 is -1 because -1 × -1 × -1 equals -1. The cube root of 2^3 is 2 because 2 × 2 × 2 equals 8. The cube root of 3^3 is 3 because 3 × 3 × 3 equals 27.

Therefore, the cube root of -108a^4b^3 simplifies to -1 × 2a^1b × 3.

In simpler form, the cube root of -108a^4b^3 is -2a^1b × 3, which can be further simplified to -2ab × 3 or -6ab.

Nice

-3ba * cuberoot of 4a

I'm sorry, could you please provide more context or a question prompt?