To determine whether a pancreas is functioning normally, a tracer dye is injected. A normally functioning pancrease secretes 4% of the dye each minute. A doctor injects 0.5g of the dye, and checks twenty minutes later. He finds that 0.35g of the dye remains If the pancreas were functioning normally, how much dye should he have found?
.96^20 = .442
.5 * .442 = .221 g should be left
Thanks a bunch!!! But wat do u do with the 0.35??? Is it useless?
To determine how much dye should remain if the pancreas were functioning normally, we can calculate the total amount of dye secreted by the pancreas in 20 minutes.
The pancreas secretes 4% of the dye every minute, so in 20 minutes it would have secreted 4% * 20 = 80% of the dye.
Therefore, the doctor should have found 100% - 80% = 20% of the dye remaining if the pancreas were functioning normally.
To calculate the amount of dye that should remain, we can multiply the initial amount of dye injected by the percentage that should remain:
0.5g * (20/100) = 0.5 * 0.2 = 0.1g
Therefore, if the pancreas were functioning normally, the doctor should have found 0.1g of dye remaining.
To determine how much dye the doctor should have found if the pancreas were functioning normally, we need to calculate the amount of dye that should have been secreted by the pancreas during the twenty minutes.
We know that a normally functioning pancreas secretes 4% of the dye each minute. So, let's calculate how much dye would be secreted in twenty minutes:
Amount of dye secreted in one minute = 4% of 0.5g
Amount of dye secreted in twenty minutes = 20 * (4% of 0.5g)
To find 4% of 0.5g, we multiply 0.5g by 4% (0.04):
Amount of dye secreted in twenty minutes = 20 * (0.04 * 0.5g)
= 20 * 0.02g
= 0.4g
Therefore, if the pancreas were functioning normally, the doctor should have found 0.4g of the dye remaining after twenty minutes.