Tuesday
October 21, 2014

Homework Help: physics

Posted by tae on Tuesday, April 23, 2013 at 5:45pm.

A particle moves through an xyz coordinate system while a force acts on it. When the particle has the position vector vector r = (2.00 m)ihat - (3.00 m)jhat + (2.00 m)khat, the force is vector F = Fxihat + (7.00 N)jhat - (5.30 N)khat and the corresponding torque about the origin is = (1.90 Nm)ihat + (-1.60 Nm)jhat + (-4.30 Nm)khat. Determine Fx.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

physics - A particle moves through an xyz coordinate system while a force acts ...
Physics - A particle is in uniform circular motion about the origin of an xy ...
phys - At t= 0, a particle starts from rest at x= 0, y= 0, and moves in the xy ...
General Physics - A force Fx acts on a particle. The force is related to the ...
Physics - The acceleration of a particle moving only on a horizontal xy plane is...
physics - A particle moves along a straight path through displacement i = (2.2 m...
physics - At a certain instant, a particle-like object is acted on by a force F...
physics - The acceleration of a particle moving only on a horizontal plane is ...
physics - The acceleration of a particle moving only on a horizontal plane is ...
Physics - The vector position of a 3.00 g particle moving in the xy plane varies...

Search
Members