Posted by **tae** on Tuesday, April 23, 2013 at 5:45pm.

At the instant the displacement of a 2.00 kg object relative to the origin is d = (2.00 m) ihat + (4.00 m) jhat - (3.00 m) khat, its velocity is v = - (6.20 m/s) ihat + (2.70 m/s) jhat + (2.60 m/s) khat, and it is subject to a force F = (6.00 N) ihat - (7.70 N) jhat + (4.10 N) khat.

(a) Find the acceleration of the object.

The jhat, khat, and the ihat.

(b) Find the angular momentum of the object about the origin.

The jhat, khat, and the ihat.

(c) Find the torque about the origin acting on the object.

The jhat, khat, and the ihat.

(d) Find the angle between the velocity of the object and the force acting on the object.

The jhat, khat, and the ihat.

## Answer this Question

## Related Questions

- physics - At a certain instant, a particle-like object is acted on by a force F...
- physics - A particle moves through an xyz coordinate system while a force acts ...
- physics - A particle moves through an xyz coordinate system while a force acts ...
- physics - If d1 = 7 ihat - 2 jhat + 4 khat and d2 = -5 ihat + 2 jhat - khat, ...
- Physics - A particle is in uniform circular motion about the origin of an xy ...
- physics - At the instant the displacement of a 2.00 kg object relative to the ...
- Physics-calc - Suppose the position of an object is given by ->r(vector) = (3...
- PHysics - A 3.00 kg object has a velocity (5.20 ihat - 2.40 jhat) m/s. (Note: ...
- Physics urgent help needed! - Suppose the position of an object is given by ->...
- physics - Let ->V1= -6.1 ihat + 8.0 jhat and ->V2 = -4.8 jhat + 4.2 ihat. ...