Posted by Anonymous on Sunday, April 21, 2013 at 11:12pm.
Simplify.
1. (1/log base 3 of 60)+ (1/log base 4 of 60)+ (1/log base 5 of 60)
2. (log base 16 of x)+ ( log base 4 of x) + (log base 2 of x)=7

Algebra 2 ..  Steve, Monday, April 22, 2013 at 12:26am
1/log_a(b) = log_b(a), so what you have is
log_60(3) + log_60(4) + log_60(5)
= log_60(3*4*5)
= log_60(60)
= 1
since 16=2^4=4^2, you have
log_16(x) + 2log_16(x) + 4log_16(x) = 7
7log_16(x) = 7
log_16(x) = 1
x=16

Algebra 2 ..  Anonymous, Monday, April 22, 2013 at 10:13am
3 · u · 7v + 8v  6uv
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