Sunday

December 21, 2014

December 21, 2014

Posted by **Anonymous** on Sunday, April 21, 2013 at 11:12pm.

1. (1/log base 3 of 60)+ (1/log base 4 of 60)+ (1/log base 5 of 60)

2. (log base 16 of x)+ ( log base 4 of x) + (log base 2 of x)=7

- Algebra 2 .. -
**Steve**, Monday, April 22, 2013 at 12:26am1/log_a(b) = log_b(a), so what you have is

log_60(3) + log_60(4) + log_60(5)

= log_60(3*4*5)

= log_60(60)

= 1

since 16=2^4=4^2, you have

log_16(x) + 2log_16(x) + 4log_16(x) = 7

7log_16(x) = 7

log_16(x) = 1

x=16

- Algebra 2 .. -
**Anonymous**, Monday, April 22, 2013 at 10:13am-3 · -u · -7v + 8v - 6uv

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