posted by Emily on .
"How would you prepare 150. mL of 0.1M sodium hydroxide given a stock solution of 3.0M NaOH?"
I made calculations and figured the process would be to dilute 5 mL of the 3.0M NaOH to 150. mL. Is this correct?
For the ideal 150. mL of 0.1M NaOH, I calculated there to need .015 mol of NaOH in the solution, which is present in 5 mL of 3.0M NaOH.