A mixture of He Ne and 3rd gas exhibit a total pressure of 486 mm hg if the partial pressure of He125mm mm hg and partial pressure of Ne is 214mm hg what is the mole fraction of the 3rd gas in container
XHe = pHe/total P
XNe = pNe/total P
XHe + XNe + Xunknown = 1.00
Substitute for XHe and XNe and solve for Xunknown.
Thanks!!!
To find the mole fraction of the third gas in the container, we need to consider the total pressure and the partial pressures of the other gases.
First, let's determine the partial pressure of the third gas by subtracting the partial pressures of helium and neon from the total pressure:
Partial pressure of the third gas = Total pressure - Partial pressure of helium - Partial pressure of neon
= 486 mmHg - 125 mmHg - 214 mmHg
= 147 mmHg
Now, to find the mole fraction of the third gas, we need to compare its partial pressure to the total pressure.
Mole fraction of the third gas = Partial pressure of the third gas / Total pressure
= 147 mmHg / 486 mmHg
≈ 0.302
Therefore, the mole fraction of the third gas in the container is approximately 0.302, or 30.2%.