# Geometery

posted by on .

Composite figure finding area.

Is this right my answer I came out with is 323.5 cm?

Rectangle:

A=22cm x 17cm = 374

(Long side is 22cm, Width is 17cm.)

Triangle:

A = 1/2 x b x h
A = 1/2 x 19cm ( no height given)

So then, I added the rectangle and trinagle sum together and came with 323.5 cm.

• Geometery - ,

• Geometery - ,

Is my answer right? Also, if not is my triangle formula wrong?

• Geometery - ,

Can't tell if ans. is right if I don't know the question.

• Geometery - ,

Composite figure finding area.

Rectangle:

A=22cm x 17cm = 374 area of rectangle

(Long side is 22cm, Width is 17cm.)

Triangle:

A = 1/2 x b x h
A = 1/2 x 19cm ( no height given)
A= 9.5 area of Triangle

I added 323.5cm + 9.5cm = 333cm area of the composite figure.

Is the the right answer 333cm area of the composite figure?

• Geometery - ,

If no height is given for the triangle, you cannot find the area. Does the triangle share a side with the rectangle? Could it be that the height of the triangle is one of the sides of the rectangle?
Your area for the rectangle is correct.

• Geometery - ,

Sorry I added 374.5 (actual calculation of rectangle area) to 9.5 = 384cm total area of the composite figure is what I meant to type.

• Geometery - ,

Yes I see what your saying. The bottom of the triangle though is apart of the side of the rectangle. But just a small portion of it. I knew my triangle something was off.

A = 1/2 x 10cm???x 19cm

The rectangle 10cm is paraelle to 22cm.

• Geometery think I got it - ,

I think I figured it out. The triangle.

A= 1/2 x bxh
A = 1/2 x 19 x 12 = 114cm area of for Triangle.

I got the 12 because the paraelel side of 10 is 22 of the rectangle. So the triangle looks like (attached to rect.) it is 12cm.

• Geometery - ,

Good job.