If 10.4 liters of O2 at STP are produced by the electrolysis of water, how many coulombs of charge were required?
chem - DrBob222, Saturday, April 20, 2013 at 6:03pm
96,485 coulombs will produce 32/2 = 16 g O2 or 11.2L O2 @ STP. Therefore,
C = 96,485 x 10.4/11.2 = ?
chem - sarah, Sunday, April 21, 2013 at 8:18pm
i got 89593.2 but its wrong
chem - DrBob222, Monday, April 22, 2013 at 12:51pm
I suspect you are keying in too many significant figures. 10.4L limits you to 3 s.f.; you're keying in 6 s.f. You may also want to try using 96,500 for 1 Faraday to make that 3 s.f. also.