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November 28, 2014

November 28, 2014

Posted by **Mary** on Saturday, April 20, 2013 at 4:50pm.

A plane has a speed of 250mph and flies with a bearing of N35degE. The wind is blowing from the west at 25 mph with a heading of due east. What is the actual speed and heading of the plane?

- Trig -
**Mary**, Saturday, April 20, 2013 at 4:51pmWhoops I forgot to include the diagram...here it is:

i.imgur [dot] com/RRY5pox.png

- Trig -
**Reiny**, Saturday, April 20, 2013 at 10:02pmI would tack on the wind vector to the end of the plane vector at the point P so the final end point is Q

Join Q to the origin O

vector OQ has our required direction and its magnitude represents the actual speed

By simple geometry angle P = 125°

so by the cosine law:

OP^2 = 250^2 + 25^2 - 2(250)(25)cos 125°

= 70294.705..

OP = 265.13

So the actual speed is 265.13 mph

Let the additional angle be Ø

by the sine law:

sinØ/25 = sin 125/265.13

sinØ = .07724

Ø = 4.43°

Ø + 35° = 39.43°

So the heading should be N 39.43° E

- Trig -
**Mary**, Sunday, April 21, 2013 at 12:29pmThank you <3 you are a lifesaver!

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