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March 29, 2015

March 29, 2015

Posted by **PLEASE HELP ME!** on Friday, April 19, 2013 at 6:06pm.

s(t) = 189t − t^3, where " is measured in metres.

a) What is the velocity of the shuttle at touchdown?

b) How much time is required for the shuttle to stop completely?

c) How far does the shuttle travel from touchdown to a complete stop?

d) What is the deceleration 8 seconds after touchdown?

- calculus (gr 12) -
**Elena**, Saturday, April 20, 2013 at 3:04pms= 189t- t³

v=ds/dt = 189-3t²

t=0 = > v=189 m/s.

189-3t² = 0

t=√(189/3) =√63 = 7.94 s.

s=189 t- t³=

=189(7.94) -7.94³=1000.1 m

a=dv/dt =d(189-3t²)/dt= - 6t

t=8 => a= - 6•8 = - 48 m/s²

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