I really need help please!!

Karen, Gavin, Nasra, and Ali each have a deck of cards. Each student randomly draws a card from the deck. Find the probability of each event.

a) each student draws a club.
b) Karen draws a red card, Gavin draws a king, Nasra draws a black card, Ali draws a 2 of clubs

c) Karen draws a heart, Gavin draws a heart, Nasra draws a face card, Ali draws an ace

a) 1/4 * 1/4 * 1/4 * 1/4

b) 1/2 * 1/13 * 1/2 * 1/52
c) 1/4 * 1/4 * 3/13 * 1/13

To find the probabilities of these events, we need to know the total number of cards in the deck and the number of cards satisfying each event. Let's assume that each deck contains 52 cards, as is typical for a standard deck of playing cards.

a) Each student draws a club:
- In a standard deck, there are 13 clubs.
- Since each student randomly selects one card, the number of favorable outcomes for this event is 13, as each student needs to draw a club.
- The total number of outcomes is 52, as there are 52 cards in the deck.
- Therefore, the probability of each student drawing a club is (13/52) * (13/52) * (13/52) * (13/52) = 0.0202, or approximately 2.02%.

b) Karen draws a red card, Gavin draws a king, Nasra draws a black card, Ali draws a 2 of clubs:
- There are 26 red cards in a standard deck (13 hearts and 13 diamonds).
- There are 4 kings in a standard deck (1 king in each suit).
- There are 26 black cards (13 clubs and 13 spades).
- There is only one 2 of clubs in a standard deck.
- The number of favorable outcomes for this event is 26 * 4 * 26 * 1 = 2704.
- The total number of outcomes is still 52 since it is the same deck of cards.
- Therefore, the probability of these specific cards being drawn is 2704/52 = 52, which reduces to 52/1 or simply 1.

c) Karen draws a heart, Gavin draws a heart, Nasra draws a face card, Ali draws an ace:
- There are 13 hearts in a standard deck.
- Once Karen draws a heart, there are 12 remaining hearts.
- There are 12 face cards (3 face cards in each suit: jack, queen, and king).
- There are 4 aces in a standard deck (1 ace in each suit).
- The number of favorable outcomes for this event is 13 * 12 * 12 * 4 = 6,912.
- The total number of outcomes remains 52.
- Therefore, the probability of these specific cards being drawn is 6,912/52 = 132, which reduces to 132/1 or simply 1.