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November 26, 2014

November 26, 2014

Posted by **Gage** on Friday, April 19, 2013 at 2:22am.

- precalculus -
**Steve**, Friday, April 19, 2013 at 1:49pmjust solve

9550 = 6500e^(.18t) for t years

t = 2.137 years from 2000

Just when the amount is reached depends on how often the increase is applied.

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