Posted by Anonymous on .
A proton travels with a speed of 3.39×106 m/s
at an angle of 56.8
◦ with a magnetic ﬁeld of
0.305 T pointed in the y direction.
The charge of proton is 1.60218 × 10−19 C.
What is the magnitude of the magnetic
force on the proton?
Answer in units of N
F = Q V x B
where the x denotes a vector cross product.
The magnitude of F is Q*V*B sin56.8
= _______ Newtons