A 10 kg block sits motionless on a table in spite of an applied horizontal force of 2 N. What are the magnitudes of the reaction force and friction force acting on the block?
Since the block is at rest, the net force acting on it is zero. Therefore, the magnitudes of the reaction force and friction force are equal, each equal to the magnitude of the applied force, which is 2 N.
Well, well, well, looks like we've got a sneaky block here! Sitting motionless and defying the laws of physics, huh? Let's investigate this mystery.
Now, the applied force is 2 N, but this block is just chilling, not budging an inch. That means there must be some sneaky forces countering that applied force.
First, we have the reaction force from the table. It's like the table saying, "Hey, block, stay right where you are!" The magnitude of this reaction force is equal to the weight of the block, which is mass times gravity. So that's 10 kg times 9.8 m/s².
Next up, we've got the friction force, the ultimate party crasher. This force opposes the motion between the block and the table. Since the block isn't moving, the friction force must be equal and opposite to the applied force. So it's also 2 N.
So, the magnitude of the reaction force from the table is around 98 N, and the magnitude of the friction force is around 2 N. Just remember, next time you see a motionless block, it's probably just trying to avoid doing any work.
To determine the magnitudes of the reaction force and friction force acting on the block, we need to analyze the forces acting on it.
1. Reaction Force: The reaction force is the force exerted by the table on the block, perpendicular to the table's surface. Since the block is sitting motionless on the table, the reaction force must be equal in magnitude and opposite in direction to the force acting on the block.
Therefore, the magnitude of the reaction force is 2 N.
2. Friction Force: The friction force opposes the motion between two surfaces in contact. Since the block is motionless, the friction force must be equal in magnitude but opposite in direction to the applied force.
Therefore, the magnitude of the friction force is also 2 N.
To find the magnitudes of the reaction force and friction force acting on the block, we first need to understand the forces involved.
1. Reaction force: When an object rests on a surface, there is a normal force acting perpendicular to the surface. This force is known as the reaction force. It counterbalances the weight of the object, preventing it from sinking through the surface.
2. Friction force: When two surfaces are in contact and one tries to move or slide over the other, there is a force that opposes this motion. This force is called the friction force. It acts parallel to the surface of contact and can be either static friction or kinetic friction, depending on whether the object is at rest or moving.
In this problem, the block is motionless, which means it is at rest. This implies that the applied horizontal force of 2 N is being balanced by the friction force. Since the block is not sinking into the table, we also know that the reaction force is equal to the weight of the block.
To find the magnitudes of the reaction force and friction force, we need to use Newton's laws of motion. Here's how:
1. Calculate the weight of the block: The weight of an object is given by the equation W = m * g, where m is the mass of the object and g is the acceleration due to gravity (approximately 9.8 m/s^2). In this case, the mass of the block is 10 kg, so its weight is W = 10 kg * 9.8 m/s^2 = 98 N.
2. Determine the reaction force: Since the block is at rest on the table, the reaction force is equal in magnitude but opposite in direction to the weight of the block. Therefore, the reaction force is also 98 N.
3. Calculate the friction force: As mentioned earlier, the friction force is equal to the applied force when the object is at rest. Therefore, the friction force is 2 N.
So, in this case, the magnitude of the reaction force is 98 N, and the magnitude of the friction force is 2 N.