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How much water must be added to 6 mL of a 0.05M stock solution to diltue it to 0.02M ?

The answerI got is 15 mL. Is this correct? Thanks

  • Chemistry - ,

    Close but no cigar.
    6 mL x 0.05 = xmL*0.02
    x mL = 15.0 mL which is the final volume. Therefore, you must add 9 mL to the 6 to make 15.0. Technically, you want the final volume to be 15.0 mL; the amount you add may NOT be EXACTLY 9.0 mL since volumes are not additive.

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