Posted by **HELP ME...uRGENT!** on Thursday, April 18, 2013 at 4:08am.

The product of 2 positive integers is 1000. What is the smallest possible sum of these 2 integers?

- ALGEBRA. -
**Reiny**, Thursday, April 18, 2013 at 8:20am
possibilies

1x1000

2x500

4x250

5x200

8x125

10 x 100

20x50

25x40

40x25 --- repeating from here on

so the smallest possible sum of those factors

= 25 + 40 = 65

OR

by the "Just Think About It" theorem, the two number would have to be as close as possible to each other, that is, near the √1000

which is appr 31.6

the closest number to 31.6 which divides evenly into 1000 is 25, so the other must be 40

## Answer this Question

## Related Questions

- smallest of 3 integers - The sum of the reciprocals of three consecutive ...
- math - the sum of the reciprocals of 3 consecutive positive integers is 47 ...
- math - the sum of the reciprocals of three consecutive positive integers is ...
- Maths - The number 1000 can be written in several ways as a sum of one or more ...
- algebra!!!! please help me!!!! - The smallest possible positive value of 1−...
- math - integers - The sum of 25 consecutive integers is 1000. What is the ...
- math - the sum of the squares of four consecutive positive integers is 734. what...
- math - there are three consecutive positive integers such that the sum of the ...
- Integers - The larger of two positive integers is five more than twice the ...
- Math - Find the smallest possible sum of six consecutive integers such that none...