how many gram of h2 needed to react with 3.10 n2
N2 + 3H2 ==> 2NH3
mols N2 = grams/molar mass
Convert mols N2 to mol H2 using the coefficients in the balanced equation.
Convert mols H2 to g. g = mols x molar mass.
To determine how many grams of H2 are needed to react with 3.10 moles of N2, we need to refer to the balanced chemical equation of the reaction between N2 and H2.
The balanced chemical equation for the reaction is:
N2 + 3H2 -> 2NH3
From the equation, we can see that 1 mole of N2 reacts with 3 moles of H2 to produce 2 moles of NH3.
Therefore, we can set up a proportion to find out the amount of H2 needed:
(3 moles of H2) / (1 mole of N2) = (x moles of H2) / (3.10 moles of N2)
Cross-multiplying the proportions:
3.10 moles of N2 * 3 moles of H2 = 1 mole of N2 * x moles of H2
9.30 moles of H2 = x moles of H2
Now, convert the moles of H2 to grams using its molar mass. The molar mass of H2 is approximately 2 g/mol.
9.30 moles of H2 * 2 g/mol = 18.6 grams of H2
Therefore, 18.6 grams of H2 are needed to react with 3.10 moles of N2.