Posted by Cherie on .
Every time Jim shoots a free throw in basketball, he has an 80% chance of making the shot. He is given 3 free throws. Find the probability of each event.
a) misses all 3 shots
b) misses the first two shots and makes the third.
Can someone please explain to me how to get the answer? Thank you

Math 
bobpursley,
They are independent events. Multiply the probabilities
prob making=.8 probab missin=.2
a. mass all three: .2*.2*.2
misstwo, make last: .2*.2*.8