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February 28, 2015

February 28, 2015

Posted by **i am dying helppp** on Wednesday, April 17, 2013 at 9:44pm.

sketching the graph of each function.

a) f(x) = x^2 − 4x + 3 , 0 ≤ x ≤ 3

b) f(x) = (x − 1)^2 , 0 ≤ x ≤ 2

- Grade 12 Calculus -
**Reiny**, Wednesday, April 17, 2013 at 10:59pmI will do the first, you do the 2nd

a) y = x^2 - 4x + 3

dy/dx = 2x - 4 = 0 for max/min

2x=4

x = 2

if x=2, y = 4 - 16 + 3 = -9

if x = 0, y = 3

if x = 3 , y = 9 - 12+3 = 0

the min is -9 and the max is 3

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