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March 2, 2015

March 2, 2015

Posted by **PLEASE HELP** on Wednesday, April 17, 2013 at 9:43pm.

a) = 2x^3 − 9x^2 ,−2 ≤ x ≤ 4

b) = 12x − x^3 , x∈ [−3,5]

- CALC -
**Reiny**, Wednesday, April 17, 2013 at 10:53pmI will do the first one, you do the second in the same way

a) y = 2x^3 - 9x^2 , -2 ≤ x ≤ 4

dy/dx = 6x^2 - 18x

= 0 for a max/min

6x(x-3) = 0

x = 0 or x = 3, both are within our given domain

if x = 0 , y = 0

if x = 3 , y = 56 - 81 = -27

so the max is 0 and the min is -27

- CALC -
**Reiny**, Wednesday, April 17, 2013 at 10:56pmshould have checked the end points

if x = -2 , y = -16 - 36 = -52

if x = 4 , y = -16

revised answer:

the max is 0 and the min is -52 within the given domain.

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