Posted by **HELP MEE** on Wednesday, April 17, 2013 at 9:43pm.

Determine the velocity and acceleration as functions of time, t, for s(t) = 45t − 5t^2, where

s(t) represents the distance as a function of time. (Hint: velocity and acceleration correspond to the first and

second derivatives of the distance)

- calculus (gr 12) -
**Reiny**, Wednesday, April 17, 2013 at 10:50pm
v = 45 - 10t

a = -10

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