Physics
posted by Joe on .
A singly charged positive ion has a mass of 2.74 1026 kg. After being accelerated through a potential difference of 268 V, the ion enters a magnetic field of 0.450 T, in a direction perpendicular to the field. Calculate the radius of the ion's path in the field.
cm

mv²/2 =eU
v=sqrt(2eU/m)=…
mv²/R=evB
R= mv/eB=…