If you begin with 10. liters of 0.15 M NaCl, what mass of NaOH can be formed?

2 NaCl(aq) + 2 H2O(liq) �¨ H2(g) + Cl2(g) + 2 NaOH(aq)

10L of .15M solution contains 1.5 moles NaCl.

Each mole of NaCl produces 1 mole of NaOH

So, how many grams in 1.5 moles NaOH?

I don't know asking for help and how to work it out.

To find the mass of NaOH that can be formed, we need to first determine the number of moles of NaCl present.

Step 1: Calculate the number of moles of NaCl.

Given:
Initial volume of NaCl solution (V) = 10.0 L
Molar concentration of NaCl (M) = 0.15 M

Using the formula for molarity, we can calculate the number of moles of NaCl:
Moles of NaCl = Molar concentration (M) x Volume (V)

Moles of NaCl = 0.15 mol/L x 10.0 L
Moles of NaCl = 1.5 moles

Step 2: Calculate the maximum moles of NaOH that can be formed.

Based on the balanced equation:
2 NaCl(aq) + 2 H2O(liq) -> H2(g) + Cl2(g) + 2 NaOH(aq)

We can see that for every 2 moles of NaCl, 2 moles of NaOH are formed. Therefore, the number of moles of NaOH formed will be the same as the number of moles of NaCl.

Moles of NaOH = 1.5 moles

Step 3: Calculate the mass of NaOH.

Given:
Molar mass of NaOH = 39.997 g/mol

Using the formula for molar mass, we can calculate the mass of NaOH:
Mass of NaOH = Moles of NaOH x Molar mass of NaOH

Mass of NaOH = 1.5 moles x 39.997 g/mol
Mass of NaOH = 59.9955 g

Rounding to an appropriate number of significant figures:
Mass of NaOH ≈ 60 g

Therefore, approximately 60 grams of NaOH can be formed from 10 liters of 0.15 M NaCl solution.

To determine the mass of NaOH that can be formed from 10 liters of 0.15 M NaCl, you need to use stoichiometry and the volume of the solution.

Here are the steps to calculate the mass of NaOH:

1. Calculate the number of moles of NaCl:
Moles of NaCl = Molarity × Volume
Moles of NaCl = 0.15 M × 10 L = 1.5 moles

2. Use the balanced equation to determine the molar ratio between NaCl and NaOH:
According to the balanced equation, 2 moles of NaCl react to form 2 moles of NaOH.

3. Calculate the number of moles of NaOH formed:
Moles of NaOH = (Moles of NaCl ÷ Molar ratio)
Moles of NaOH = (1.5 moles ÷ 2) = 0.75 moles

4. Calculate the molar mass of NaOH:
The molar mass of NaOH is the sum of the atomic masses of its constituent elements:
Molar mass of NaOH = (Na: 22.99 g/mol) + (O: 16.00 g/mol) + (H: 1.01 g/mol)
Molar mass of NaOH = 39.00 g/mol

5. Calculate the mass of NaOH formed:
Mass of NaOH = (Moles of NaOH × Molar mass of NaOH)
Mass of NaOH = (0.75 moles × 39.00 g/mol)
Mass of NaOH = 29.25 grams

Therefore, the mass of NaOH that can be formed from 10 liters of 0.15 M NaCl is 29.25 grams.