A meteoroid changed velocity from 1.0 km/s to 1.8 km/s in 0.03 seconds. What is the acceleration of the meteoroid?
a = V-Vo)/t = (1.8-1)/0.03 = 26.67 m/s^2
To find the acceleration of the meteoroid, we can use the formula:
acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 1.0 km/s
Final velocity (v) = 1.8 km/s
Time (t) = 0.03 seconds
Substituting these values into the formula, we get:
acceleration = (1.8 km/s - 1.0 km/s) / 0.03 s
Simplifying, we have:
acceleration = 0.8 km/s / 0.03 s
To convert this to m/s², we need to convert km/s to m/s and divide by the square of the time conversion factor from seconds to milliseconds.
1 km = 1000 m
1 s^2 = 1000 ms
So, the acceleration in m/s² is:
acceleration = (0.8 km/s * 1000 m/km) / (0.03 s * 1000 ms/s)^2
acceleration = (800 m/s) / (0.03 s)^2
acceleration = (800 m/s) / 0.0009 s²
Therefore, the acceleration of the meteoroid is:
acceleration = 888,888.8889 m/s² (rounded to the nearest decimal place)
To find the acceleration of the meteoroid, we can use the formula:
Acceleration (a) = (Final Velocity (v_f) - Initial Velocity (v_i)) / Time (t)
Given:
Initial Velocity (v_i) = 1.0 km/s
Final Velocity (v_f) = 1.8 km/s
Time (t) = 0.03 seconds
Let's plug in the values into the formula:
a = (1.8 km/s - 1.0 km/s) / 0.03 seconds
To simplify, convert the velocities to meters per second (m/s) by multiplying by 1000:
a = (1800 m/s - 1000 m/s) / 0.03 seconds
Now subtract the velocities:
a = 800 m/s / 0.03 seconds
Finally, divide the velocity by the time:
a = 26,666.67 m/s^2
So, the acceleration of the meteoroid is 26,666.67 m/s^2.