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April 19, 2014

April 19, 2014

Posted by **OIan** on Tuesday, April 16, 2013 at 3:33am.

Details and assumptions

i is the imaginary unit, where i2=−1.

- Maths -
**Steve**, Tuesday, April 16, 2013 at 11:08amone other complex root must be 3+2i

So, (x-(3-2i))(x-(3+2i)) are factors of f(x)

That is, (x-3)^2+4 = (x^2-6x+13) divides f(x)

f(x) = (x^2-6x+13)(x^2-9x+14)

= (x^2-6x+13)(x-2)(x-7)

So, the roots are

2,7,3-2i,3+2i

You can add 'em up

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