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September 20, 2014

September 20, 2014

Posted by **Jen** on Monday, April 15, 2013 at 5:07pm.

1.5x-5/10x^2-25x+15

2.w^2+6w+9/2w^2-18

- algebra 1 -
**Steve**, Monday, April 15, 2013 at 5:28pm(5x-5)/(10x^2-25x+15)

5(x-1) / 5(2x^2-5x+3)

5(x-1) / 5(x-1)(2x-3)

Now as long as x≠1, that is just

1/(2x-3)

(w^2+6w+9)/(2w^2-18)

(w+3)(w+3) / 2(w+3)(w-3)

if x≠-3, that's

(w+3) / 2(w-3)

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