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Posted by on Monday, April 15, 2013 at 4:22pm.

Please help me. P and Q are two gun placements 1250m apart. T is a target. The angles TPQ and TQP are 73 degree 24' and 68 degree 5' respectively. Find the distance P to the target T.

  • Maths - , Monday, April 15, 2013 at 4:48pm

    you know that angle T is 8° 31'

    PT/sinQ = 1250/sinT

  • Maths - , Monday, April 15, 2013 at 4:49pm

    Hmmm. Bit of a typo there. T is 38°31'

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