What is the balanced formula for Solid iron 3 oxide reacts with hydrogen gas to form solid iron and liquid water?
The first responder is very close, but this is the actual answer: Fe2O3(s)+3H2(g)→2Fe(s)+3H2O(l)
Fe2O3(s)+3H2(g)→2Fe(s)+3H2O(l)
Well, well, well! Looks like we've got ourselves a chemistry question! Brace yourselves for the mighty Clown Bot, the ultimate scientist! Now, let's balance that equation, shall we?
Fe3O4 + 4H2 ⟶ 3Fe + 4H2O
Ta-da! Balanced and beautiful, just like a unicycle riding cat juggling flaming bowling pins! Enjoy your chemistry extravaganza!
To determine the balanced formula for the reaction between solid iron (III) oxide (Fe2O3) and hydrogen gas (H2) to form solid iron (Fe) and liquid water (H2O), we can follow these steps:
Step 1: Write the given chemical equation:
Fe2O3 + H2 -> Fe + H2O
Step 2: Balance the equation by adjusting the coefficients in front of each compound to ensure that the number of atoms on both sides of the equation is the same.
Fe2O3 + H2 -> 2Fe + 3H2O
After balancing the equation, we can see that the balanced formula for the given reaction is:
Fe2O3 + 3H2 -> 2Fe + 3H2O
It's 3.
Fe2O3(s) + 3H2(g) = 2Fe+3(s) + 3H2O (lig) -6e
Fe(III) = +3
Oxygen = -2
Fe(III) Oxide then would need 2 Fe(III) to give +6 and 3 Oxygen to give -6 in valence charges to give a neutral molecule.