Posted by chris on Monday, April 15, 2013 at 12:44am.
ok, so im stumped on this bonus system. there is a hint that the prof. gave that said that all coefficients are 1 or 1. can someone do this and explain how you did it?
a + b + c + d + e + f + g + h + k + m = 27
a – b + c + d + e + f + g + h + k + m = 23
a + b  c + d + e + f + g + h +k +m = 39
a + b + c  d + e + f + g + h + k + m = 3
a + b + c + d  e + f + g + h + k + m = 21
a + b + c + d + e  f + g + h + k + m = 13
a + b + c + d + e + f  g + h + k + m = 5
a + b + c + d + e + f + g  h + k  m = 11
a + b + c + d + e + f + g + h  k + m = 9
a + b + c + d + e + f + g + h + k  m = 1

algebraic systems  Steve, Monday, April 15, 2013 at 3:23pm
a+b+c+d+e+f+g+h+k+m = 27
a–b+c+d+e+f+g+h+k+m = 23
subtract the equations to get
2b = 4, so
b=2
work with other pairs of equations to evaluate the other variables. Look for a pair which are identical except for the ± sign on one variable.