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January 26, 2015

January 26, 2015

Posted by **Anonymous** on Sunday, April 14, 2013 at 10:58pm.

- math -
**Reiny**, Sunday, April 14, 2013 at 11:39pmIf you know Calculus,

h ' (t) = -9.8t + 9.8 = 0 for a max of h

9.8t = 9.8

t = 1

h(1) = -4/9(1) + 9.8 + 1 = 5.9 m

If you don't know Calculus, complete the square

h(t) = -4.9 [t^2 - 2t +1 - 1 ] +1

= -4.9 [ (t-1)^2 - 1 ] + 1

= -4.9(t-1)^2 + 4.9 + 1

= -4.9(t-1)^2 + 5.9

so the vertex is (1,5.9) and the parabola opens downwards

So we have a maximum of 5.9 m when t = 1 sec

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