Thursday

October 23, 2014

October 23, 2014

Posted by **gemma** on Sunday, April 14, 2013 at 8:41pm.

Prove: For any closed set A in Y, f^-1(A) is closed in X (AKA f is continuous)

X and Y are metric spaces

f: X -> Y

f^-1 is f inverse.

closure(A) = A U limit points of A

The first line is Let C be a closed subset of Y. Then we have to show that f^-1(C) is closed in X.

I have made several attempts but nothing is working. Anyone have any ideas?

30 minutes ago - 4 days left to answer.

**Answer this Question**

**Related Questions**

closure propery - Is this set closed under multiplication {-1, 0, 1}

Math - Is The Set {cos1,cos2,cos3,cos4,...} under usual topology closed??? ...

Math-- - Decide whether or not the set is closed under addition. {0, 1} A) ...

Math - Decide whether or not the set is closed under addition. {0, 1} A) Closed ...

Set Thoery - (1)Given the sets A={a,b}, B={a,b,c}, C= {b,c,d}. which of these ...

Set Theory - Given the sets A=[a,b], B=[a,b,c], C=[b,c,d] Prove that if A is a ...

Computer Science - Which abstract function(s) should be used to design: A ...

Algebra - How would you prove this theorem: The column space of an m x n matrix ...

Algebra 2 - Need help PLEASE!! Question is: There is no Closure Property of ...

Medical Coding/Billing - PROCEDURES: Excision of a 2.5 cm hemangioma on the ...