Posted by **Jacob** on Sunday, April 14, 2013 at 5:36pm.

The world population at the beginning of 1990 was 5.3 billion. Assume that the population continues to grow at the rate of approximately 2%/year and find the function Q(t) that expresses the world population (in billions) as a function of time t (in years), with t = 0 corresponding to the beginning of 1990. (Round your answers to two decimal places.)

(a). If the world population continues to grow at approximately 2%/year, find the length of time t0 required for the population to double in size.

t0=____yr

(b). Using the time t0 found in part (a), what would be the world population if the growth rate were reduced to 1.2%/yr?

____ billion people

I don't understand how to set this problem up correctly.

- Applied Calculus -
**Anonymous**, Wednesday, November 26, 2014 at 4:16pm
66

## Answer This Question

## Related Questions

- Math - he world population at the beginning of 1990 was 5.3 billion. Assume that...
- Algebra - Wk 6 Sec 12.7 #24 World population growth In 2008 the world population...
- maths - The population of the world in 1987 was 5 billion and the annual growth ...
- maths - The population of the world in 1987 was 5 billion and the annual growth ...
- calculus - The population of less-developed countries in mid-2007 of 4086 ...
- Math - The population of the Earth is approximately 6 billion people and is ...
- math 12 - The world's population is 1970 was about 3.6 billion. If the ...
- College Algebra - The population of the Earth is approximately 6 billion people...
- College Algebra - The population of the Earth is approximately 6 billion people ...
- Calculus - for population in billions, where t is years since 1990: N(t) = 41/1+...

More Related Questions