Sunday

April 20, 2014

April 20, 2014

Posted by **brenda** on Saturday, April 13, 2013 at 3:28pm.

- college algebar -
**Rosemary**, Saturday, April 13, 2013 at 4:12pmWhat is the question?

- college algebar -
**Reiny**, Saturday, April 13, 2013 at 6:37pmlogb x= logb(x+2)-logb8

logx = log [ (x+2)/8 ] , where all logs are base 8

anti-log it

x = (x+2)/8

8x = x+2

7x = 2

x = 2/7

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