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posted by brenda on Saturday, April 13, 2013 at 3:28pm.

logb x= logb(x+2)-logb8

What is the question?

logb x= logb(x+2)-logb8 logx = log [ (x+2)/8 ] , where all logs are base 8 anti-log it x = (x+2)/8 8x = x+2 7x = 2 x = 2/7

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