# Maths *have answer, want method* Urgent!

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Suppose that the blood pressure of the human inhabitants of a certain Pacific island is distributed with mean, \mu = 108 mmHg and standard deviation , \sigma = 6 mmHg. According to Chebyshev's Theorem, at least what percentage of the islanders have blood pressure in the range from 93.6 mmHg to 122.4 mmHg ?

I have the answer, but I don't understand how to get it...please help!

• Maths *have answer, want method* Urgent! - ,

82.64%

• Maths *have answer, want method* Urgent! - ,

Don't know about theorem, but here is method.

Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to your Z scores. Multiply by 100.

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