maths question I don't know how to do it h=16t2+240t-224

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Online "^" is used to indicate and exponent, e.g., x^2 = x squared.

Need to know value of either h or t to solve.

To solve the quadratic equation `h = 16t^2 + 240t - 224`, you're essentially trying to find the values of `t` that satisfy this equation. Here's how you can solve it:

Step 1: Set the equation equal to zero: `16t^2 + 240t - 224 = 0`. This is done by subtracting `h` from both sides of the equation.

Step 2: Simplify the equation if possible. In this case, the equation is already simplified, so we can move on to the next step.

Step 3: Make use of the quadratic formula: The quadratic formula is given by `t = (-b ± √(b^2 - 4ac)) / (2a)`, where `a`, `b`, and `c` are the coefficients in the equation `ax^2 + bx + c = 0`.

Comparing the given equation `16t^2 + 240t - 224 = 0` to the general quadratic equation `ax^2 + bx + c = 0`, we can see that `a = 16`, `b = 240`, and `c = -224`.

Substituting these values into the quadratic formula, we get:
`t = (-240 ± √(240^2 - 4 * 16 * -224)) / (2 * 16)`

Step 4: Simplify and calculate.
Evaluate the expression inside the square root: `√(240^2 - 4 * 16 * -224) = √(57600 + 14336) = √(71936) = 268`.

Plugging this value back into the quadratic formula, we get two possible solutions for `t`:
`t₁ = (-240 + 268) / 32 = 7/2 ≈ 3.5`
`t₂ = (-240 - 268) / 32 = -23/2 ≈ -11.5`

Thus, the solutions to the equation `h = 16t^2 + 240t - 224` are `t = 3.5` and `t = -11.5`.